12*(1-2x)/3-10(4-5)/6+12*13/12=0

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Solution for 12*(1-2x)/3-10(4-5)/6+12*13/12=0 equation: 


x in (-oo:+oo)

(12*(1-(2*x)))/3-((10*(4-5))/6)+(12*13)/12 = 0

(12*(1-2*x))/3+(-5/3)*(4-5)+(12*13)/12 = 0

(12*(1-2*x))/3+5/3+13 = 0

(12*(1-2*x))/3+5/3+(3*13)/3 = 0

12*(1-2*x)+3*13+5 = 0

17-24*x+39 = 0

56-24*x = 0

(56-24*x)/3 = 0

(56-24*x)/3 = 0 // * 3

56-24*x = 0

56-24*x = 0 // - 56

-24*x = -56 // : -24

x = -56/(-24)

x = 7/3

x = 7/3

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