12(z-4)-10(z+3)=24

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Solution for 12(z-4)-10(z+3)=24 equation:


Simplifying
12(z + -4) + -10(z + 3) = 24

Reorder the terms:
12(-4 + z) + -10(z + 3) = 24
(-4 * 12 + z * 12) + -10(z + 3) = 24
(-48 + 12z) + -10(z + 3) = 24

Reorder the terms:
-48 + 12z + -10(3 + z) = 24
-48 + 12z + (3 * -10 + z * -10) = 24
-48 + 12z + (-30 + -10z) = 24

Reorder the terms:
-48 + -30 + 12z + -10z = 24

Combine like terms: -48 + -30 = -78
-78 + 12z + -10z = 24

Combine like terms: 12z + -10z = 2z
-78 + 2z = 24

Solving
-78 + 2z = 24

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '78' to each side of the equation.
-78 + 78 + 2z = 24 + 78

Combine like terms: -78 + 78 = 0
0 + 2z = 24 + 78
2z = 24 + 78

Combine like terms: 24 + 78 = 102
2z = 102

Divide each side by '2'.
z = 51

Simplifying
z = 51

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