12(z-15)+6=18+6z

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Solution for 12(z-15)+6=18+6z equation: 



12(z-15)+6=18+6z

We move all terms to the left:

12(z-15)+6-(18+6z)=0

We add all the numbers together, and all the variables

12(z-15)-(6z+18)+6=0

We multiply parentheses

12z-(6z+18)-180+6=0

We get rid of parentheses

12z-6z-18-180+6=0

We add all the numbers together, and all the variables

6z-192=0

We move all terms containing z to the left, all other terms to the right

6z=192

z=192/6

z=32

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