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12(z+3)-4(z-3)=4(z-2)+3(z-4)
We move all terms to the left:
12(z+3)-4(z-3)-(4(z-2)+3(z-4))=0
We multiply parentheses
12z-4z-(4(z-2)+3(z-4))+36+12=0
We calculate terms in parentheses: -(4(z-2)+3(z-4)), so:We add all the numbers together, and all the variables
4(z-2)+3(z-4)
We multiply parentheses
4z+3z-8-12
We add all the numbers together, and all the variables
7z-20
Back to the equation:
-(7z-20)
8z-(7z-20)+48=0
We get rid of parentheses
8z-7z+20+48=0
We add all the numbers together, and all the variables
z+68=0
We move all terms containing z to the left, all other terms to the right
z=-68
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