12(y+4)=-8(2y+9)

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Solution for 12(y+4)=-8(2y+9) equation: 



12(y+4)=-8(2y+9)

We move all terms to the left:

12(y+4)-(-8(2y+9))=0

We multiply parentheses

12y-(-8(2y+9))+48=0



We calculate terms in parentheses: -(-8(2y+9)), so:

-8(2y+9)

We multiply parentheses

-16y-72

Back to the equation:

-(-16y-72)



We get rid of parentheses

12y+16y+72+48=0

We add all the numbers together, and all the variables

28y+120=0

We move all terms containing y to the left, all other terms to the right

28y=-120

y=-120/28

y=-4+2/7

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