12(y+1)+8=9(y-1)+26

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Solution for 12(y+1)+8=9(y-1)+26 equation: 



12(y+1)+8=9(y-1)+26

We move all terms to the left:

12(y+1)+8-(9(y-1)+26)=0

We multiply parentheses

12y-(9(y-1)+26)+12+8=0



We calculate terms in parentheses: -(9(y-1)+26), so:

9(y-1)+26

We multiply parentheses

9y-9+26

We add all the numbers together, and all the variables

9y+17

Back to the equation:

-(9y+17)



We add all the numbers together, and all the variables

12y-(9y+17)+20=0

We get rid of parentheses

12y-9y-17+20=0

We add all the numbers together, and all the variables

3y+3=0

We move all terms containing y to the left, all other terms to the right

3y=-3

y=-3/3

y=-1

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