12(x-8)=+8x(x+8)

Solution for 12(x-8)=+8x(x+8) equation:

12(x-8)=+8x(x+8)

We move all terms to the left:

12(x-8)-(+8x(x+8))=0

We multiply parentheses

12x-(+8x(x+8))-96=0


We calculate terms in parentheses: -(+8x(x+8)), so:

+8x(x+8)

determiningTheFunctionDomain
8x(x+8)

We multiply parentheses

8x^2+64x

Back to the equation:

-(8x^2+64x)


We get rid of parentheses

-8x^2+12x-64x-96=0

We add all the numbers together, and all the variables

-8x^2-52x-96=0

a = -8; b = -52; c = -96;
Δ = b2-4ac
Δ = -522-4·(-8)·(-96)
Δ = -368
Delta is less than zero, so there is no solution for the equation