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12(x-5)=35
We move all terms to the left:
12(x-5)-(35)=0
We multiply parentheses
12x-60-35=0
We add all the numbers together, and all the variables
12x-95=0
We move all terms containing x to the left, all other terms to the right
12x=95
x=95/12
x=7+11/12
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