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12(x-4)-5x=10-3x
We move all terms to the left:
12(x-4)-5x-(10-3x)=0
We add all the numbers together, and all the variables
12(x-4)-5x-(-3x+10)=0
We add all the numbers together, and all the variables
-5x+12(x-4)-(-3x+10)=0
We multiply parentheses
-5x+12x-(-3x+10)-48=0
We get rid of parentheses
-5x+12x+3x-10-48=0
We add all the numbers together, and all the variables
10x-58=0
We move all terms containing x to the left, all other terms to the right
10x=58
x=58/10
x=5+4/5
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