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12(x-3)=7(x+5)+4
We move all terms to the left:
12(x-3)-(7(x+5)+4)=0
We multiply parentheses
12x-(7(x+5)+4)-36=0
We calculate terms in parentheses: -(7(x+5)+4), so:We get rid of parentheses
7(x+5)+4
We multiply parentheses
7x+35+4
We add all the numbers together, and all the variables
7x+39
Back to the equation:
-(7x+39)
12x-7x-39-36=0
We add all the numbers together, and all the variables
5x-75=0
We move all terms containing x to the left, all other terms to the right
5x=75
x=75/5
x=15
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