12(x-3)=2(6x-4)-28

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Solution for 12(x-3)=2(6x-4)-28 equation:


12(x-3)=2(6x-4)-28

We simplify the equation to the form, which is simple to understand
12(x-3)=2(6x-4)-28

Reorder the terms in parentheses
+(+12x-36)=2*(6x-4)-28

Remove unnecessary parentheses
+12x-36=+2+*(+6x-4+)-28

Reorder the terms in parentheses
+12x-36=+(+12x-8)-28

Remove unnecessary parentheses
+12x-36=+12x-8-28

We move all terms containing x to the left and all other terms to the right.
+12x-12x=-8-28+36

We simplify left and right side of the equation.
0x=0

0=0

This equation is an identity, so all real numbers are solutions.

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