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12(x-3)-8(4-x)-3(2x-9)=19-6x
We move all terms to the left:
12(x-3)-8(4-x)-3(2x-9)-(19-6x)=0
We add all the numbers together, and all the variables
12(x-3)-8(-1x+4)-3(2x-9)-(-6x+19)=0
We multiply parentheses
12x+8x-6x-(-6x+19)-36-32+27=0
We get rid of parentheses
12x+8x-6x+6x-19-36-32+27=0
We add all the numbers together, and all the variables
20x-60=0
We move all terms containing x to the left, all other terms to the right
20x=60
x=60/20
x=3
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