12(x-3)+3x=1/3(x+12)+10x

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Solution for 12(x-3)+3x=1/3(x+12)+10x equation: 



12(x-3)+3x=1/3(x+12)+10x

We move all terms to the left:

12(x-3)+3x-(1/3(x+12)+10x)=0



Domain of the equation: 3(x+12)+10x)!=0

x∈R



We add all the numbers together, and all the variables

3x+12(x-3)-(1/3(x+12)+10x)=0

We multiply parentheses

3x+12x-(1/3(x+12)+10x)-36=0

We multiply all the terms by the denominator


3x*3(x+12)+10x)+12x*3(x+12)+10x)-(1-36*3(x+12)+10x)=0

Wy multiply elements

9x^2(x+10x)+12x*3(x+12)+10x)-(1-36*3(x+12)+10x)=0

We add all the numbers together, and all the variables

9x^2(+11x)+12x*3(x+12)+10x)-(1-36*3(x+12)+10x)=0

Wy multiply elements

9x^2(+11x)+36x^2(x+10x)-(1-108x(x+10x)=0



We calculate terms in parentheses: -(1-108x(x+10x), so:

1-108x(x+10x

determiningTheFunctionDomain
-108x(x+10x+1

Back to the equation:

-(-108x(x+10x+1)



We add all the numbers together, and all the variables

9x^2(+11x)+36x^2(+11x)-(-108x(11x+1)=0



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-108x(11x+1





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-108x(11x+1





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-108x(11x+1





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-108x(11x+1





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-108x(11x+1





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-108x(11x+1





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-108x(11x+1





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