12(x-2)+3x=13(x+12)+10x

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Solution for 12(x-2)+3x=13(x+12)+10x equation: 



12(x-2)+3x=13(x+12)+10x

We move all terms to the left:

12(x-2)+3x-(13(x+12)+10x)=0

We add all the numbers together, and all the variables

3x+12(x-2)-(13(x+12)+10x)=0

We multiply parentheses

3x+12x-(13(x+12)+10x)-24=0



We calculate terms in parentheses: -(13(x+12)+10x), so:

13(x+12)+10x

We add all the numbers together, and all the variables

10x+13(x+12)

We multiply parentheses

10x+13x+156

We add all the numbers together, and all the variables

23x+156

Back to the equation:

-(23x+156)



We add all the numbers together, and all the variables

15x-(23x+156)-24=0

We get rid of parentheses

15x-23x-156-24=0

We add all the numbers together, and all the variables

-8x-180=0

We move all terms containing x to the left, all other terms to the right

-8x=180

x=180/-8

x=-22+1/2

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