12(x-2)+3x=1/2(x=6)+2

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Solution for 12(x-2)+3x=1/2(x=6)+2 equation: 



12(x-2)+3x=1/2(x=6)+2

We move all terms to the left:

12(x-2)+3x-(1/2(x)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We add all the numbers together, and all the variables

3x+12(x-2)-(1/2x=0

We multiply parentheses

3x+12x-(1/2x-24=0

We multiply all the terms by the denominator


3x*2x+12x*2x-24-24-(1=0

We add all the numbers together, and all the variables

3x*2x+12x*2x=0

Wy multiply elements

6x^2+24x^2=0

We add all the numbers together, and all the variables

30x^2=0

a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{60}=0$

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