12(x-2)+3x=0.3(x+12)+10x

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Solution for 12(x-2)+3x=0.3(x+12)+10x equation: 



12(x-2)+3x=0.3(x+12)+10x

We move all terms to the left:

12(x-2)+3x-(0.3(x+12)+10x)=0

We add all the numbers together, and all the variables

3x+12(x-2)-(0.3(x+12)+10x)=0

We multiply parentheses

3x+12x-(0.3(x+12)+10x)-24=0



We calculate terms in parentheses: -(0.3(x+12)+10x), so:

0.3(x+12)+10x

We add all the numbers together, and all the variables

10x+0.3(x+12)

We multiply parentheses

10x+0.3x+3.6

We add all the numbers together, and all the variables

10.3x+3.6

Back to the equation:

-(10.3x+3.6)



We add all the numbers together, and all the variables

15x-(10.3x+3.6)-24=0

We get rid of parentheses

15x-10.3x-3.6-24=0

We add all the numbers together, and all the variables

4.7x-27.6=0

We move all terms containing x to the left, all other terms to the right

4.7x=27.6

x=27.6/4.7

x=5+1/1.1463414634146

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