12(x-2)+3x=(x+12)+10x

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Solution for 12(x-2)+3x=(x+12)+10x equation: 



12(x-2)+3x=(x+12)+10x

We move all terms to the left:

12(x-2)+3x-((x+12)+10x)=0

We add all the numbers together, and all the variables

3x+12(x-2)-((x+12)+10x)=0

We multiply parentheses

3x+12x-((x+12)+10x)-24=0



We calculate terms in parentheses: -((x+12)+10x), so:

(x+12)+10x

We add all the numbers together, and all the variables

10x+(x+12)

We get rid of parentheses

10x+x+12

We add all the numbers together, and all the variables

11x+12

Back to the equation:

-(11x+12)



We add all the numbers together, and all the variables

15x-(11x+12)-24=0

We get rid of parentheses

15x-11x-12-24=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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