12(x-2)+3x=(1/2)(x+6)+2

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Solution for 12(x-2)+3x=(1/2)(x+6)+2 equation: 



12(x-2)+3x=(1/2)(x+6)+2

We move all terms to the left:

12(x-2)+3x-((1/2)(x+6)+2)=0



Domain of the equation: 2)(x+6)+2)!=0

x∈R



We add all the numbers together, and all the variables

12(x-2)+3x-((+1/2)(x+6)+2)=0

We add all the numbers together, and all the variables

3x+12(x-2)-((+1/2)(x+6)+2)=0

We multiply parentheses

3x+12x-((+1/2)(x+6)+2)-24=0

We multiply parentheses ..

-((+x^2+1/2*6)+2)+3x+12x-24=0

We multiply all the terms by the denominator


-((+x^2+1+3x*2*6)+2)+12x*2*6)+2)-24*2*6)+2)=0



We calculate terms in parentheses: -((+x^2+1+3x*2*6)+2), so:

(+x^2+1+3x*2*6)+2

We get rid of parentheses

x^2+3x*2*6+1+2

We add all the numbers together, and all the variables

x^2+3x*2*6+3

Wy multiply elements

x^2+36x*6+3

Wy multiply elements

x^2+216x+3

Back to the equation:

-(x^2+216x+3)



Wy multiply elements

1728x^3*6-(x^2+216x+3)=0

We get rid of parentheses

1728x^3*6-x^2-216x-3=0

We do not support expression: x^3

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