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12(x-1)=6(2x+5)-42
We move all terms to the left:
12(x-1)-(6(2x+5)-42)=0
We multiply parentheses
12x-(6(2x+5)-42)-12=0
We calculate terms in parentheses: -(6(2x+5)-42), so:We get rid of parentheses
6(2x+5)-42
We multiply parentheses
12x+30-42
We add all the numbers together, and all the variables
12x-12
Back to the equation:
-(12x-12)
12x-12x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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