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12(x-1)=6(2-x)+6x
We move all terms to the left:
12(x-1)-(6(2-x)+6x)=0
We add all the numbers together, and all the variables
12(x-1)-(6(-1x+2)+6x)=0
We multiply parentheses
12x-(6(-1x+2)+6x)-12=0
We calculate terms in parentheses: -(6(-1x+2)+6x), so:We add all the numbers together, and all the variables
6(-1x+2)+6x
We add all the numbers together, and all the variables
6x+6(-1x+2)
We multiply parentheses
6x-6x+12
We add all the numbers together, and all the variables
12
Back to the equation:
-(12)
12x-24=0
We move all terms containing x to the left, all other terms to the right
12x=24
x=24/12
x=2
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