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12(x-1)=3(4-x)+9x
We move all terms to the left:
12(x-1)-(3(4-x)+9x)=0
We add all the numbers together, and all the variables
12(x-1)-(3(-1x+4)+9x)=0
We multiply parentheses
12x-(3(-1x+4)+9x)-12=0
We calculate terms in parentheses: -(3(-1x+4)+9x), so:We get rid of parentheses
3(-1x+4)+9x
We add all the numbers together, and all the variables
9x+3(-1x+4)
We multiply parentheses
9x-3x+12
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
12x-6x-12-12=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4
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