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12(x+5)=-3(x-20)
We move all terms to the left:
12(x+5)-(-3(x-20))=0
We multiply parentheses
12x-(-3(x-20))+60=0
We calculate terms in parentheses: -(-3(x-20)), so:We get rid of parentheses
-3(x-20)
We multiply parentheses
-3x+60
Back to the equation:
-(-3x+60)
12x+3x-60+60=0
We add all the numbers together, and all the variables
15x=0
x=0/15
x=0
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