12(x+4)=4(3+4)+32

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Solution for 12(x+4)=4(3+4)+32 equation: 



12(x+4)=4(3+4)+32

We move all terms to the left:

12(x+4)-(4(3+4)+32)=0

We add all the numbers together, and all the variables

12(x+4)-(47+32)=0

We add all the numbers together, and all the variables

12(x+4)-79=0

We multiply parentheses

12x+48-79=0

We add all the numbers together, and all the variables

12x-31=0

We move all terms containing x to the left, all other terms to the right

12x=31

x=31/12

x=2+7/12

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