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12(v+4)-4v=4(2v+2)-15
We move all terms to the left:
12(v+4)-4v-(4(2v+2)-15)=0
We add all the numbers together, and all the variables
-4v+12(v+4)-(4(2v+2)-15)=0
We multiply parentheses
-4v+12v-(4(2v+2)-15)+48=0
We calculate terms in parentheses: -(4(2v+2)-15), so:We add all the numbers together, and all the variables
4(2v+2)-15
We multiply parentheses
8v+8-15
We add all the numbers together, and all the variables
8v-7
Back to the equation:
-(8v-7)
8v-(8v-7)+48=0
We get rid of parentheses
8v-8v+7+48=0
We add all the numbers together, and all the variables
55!=0
There is no solution for this equation
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