12(v+1)-4v=2(4v+3)-8

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Solution for 12(v+1)-4v=2(4v+3)-8 equation:



12(v+1)-4v=2(4v+3)-8
We move all terms to the left:
12(v+1)-4v-(2(4v+3)-8)=0
We add all the numbers together, and all the variables
-4v+12(v+1)-(2(4v+3)-8)=0
We multiply parentheses
-4v+12v-(2(4v+3)-8)+12=0
We calculate terms in parentheses: -(2(4v+3)-8), so:
2(4v+3)-8
We multiply parentheses
8v+6-8
We add all the numbers together, and all the variables
8v-2
Back to the equation:
-(8v-2)
We add all the numbers together, and all the variables
8v-(8v-2)+12=0
We get rid of parentheses
8v-8v+2+12=0
We add all the numbers together, and all the variables
14!=0
There is no solution for this equation

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