12(t-5)+6t=(3t+4)-11

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Solution for 12(t-5)+6t=(3t+4)-11 equation: 



12(t-5)+6t=(3t+4)-11

We move all terms to the left:

12(t-5)+6t-((3t+4)-11)=0

We add all the numbers together, and all the variables

6t+12(t-5)-((3t+4)-11)=0

We multiply parentheses

6t+12t-((3t+4)-11)-60=0



We calculate terms in parentheses: -((3t+4)-11), so:

(3t+4)-11

We get rid of parentheses

3t+4-11

We add all the numbers together, and all the variables

3t-7

Back to the equation:

-(3t-7)



We add all the numbers together, and all the variables

18t-(3t-7)-60=0

We get rid of parentheses

18t-3t+7-60=0

We add all the numbers together, and all the variables

15t-53=0

We move all terms containing t to the left, all other terms to the right

15t=53

t=53/15

t=3+8/15

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