12(t+28)=444

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Solution for 12(t+28)=444 equation: 



12(t+28)=444

We move all terms to the left:

12(t+28)-(444)=0

We multiply parentheses

12t+336-444=0

We add all the numbers together, and all the variables

12t-108=0

We move all terms containing t to the left, all other terms to the right

12t=108

t=108/12

t=9

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