12(n-20)=48

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Solution for 12(n-20)=48 equation:



12(n-20)=48
We move all terms to the left:
12(n-20)-(48)=0
We multiply parentheses
12n-240-48=0
We add all the numbers together, and all the variables
12n-288=0
We move all terms containing n to the left, all other terms to the right
12n=288
n=288/12
n=24

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