12(n+5)=3(20)+4n)

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Solution for 12(n+5)=3(20)+4n) equation: 



12(n+5)=3(20)+4n)

We move all terms to the left:

12(n+5)-(3(20)+4n))=0

We add all the numbers together, and all the variables

12(n+5)-(4n+320))=0

We multiply parentheses

12n-(4n+320))+60=0

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