12(n+3)=8(n-1)

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Solution for 12(n+3)=8(n-1) equation: 



12(n+3)=8(n-1)

We move all terms to the left:

12(n+3)-(8(n-1))=0

We multiply parentheses

12n-(8(n-1))+36=0



We calculate terms in parentheses: -(8(n-1)), so:

8(n-1)

We multiply parentheses

8n-8

Back to the equation:

-(8n-8)



We get rid of parentheses

12n-8n+8+36=0

We add all the numbers together, and all the variables

4n+44=0

We move all terms containing n to the left, all other terms to the right

4n=-44

n=-44/4

n=-11

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