12(m+3)=4(2m+9)+4m

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Solution for 12(m+3)=4(2m+9)+4m equation: 



12(m+3)=4(2m+9)+4m

We move all terms to the left:

12(m+3)-(4(2m+9)+4m)=0

We multiply parentheses

12m-(4(2m+9)+4m)+36=0



We calculate terms in parentheses: -(4(2m+9)+4m), so:

4(2m+9)+4m

We add all the numbers together, and all the variables

4m+4(2m+9)

We multiply parentheses

4m+8m+36

We add all the numbers together, and all the variables

12m+36

Back to the equation:

-(12m+36)



We get rid of parentheses

12m-12m-36+36=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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