12(c+3d+4f)+2(2c+d+6f)=

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Solution for 12(c+3d+4f)+2(2c+d+6f)= equation:


Simplifying
12(c + 3d + 4f) + 2(2c + d + 6f) = 0
(c * 12 + 3d * 12 + 4f * 12) + 2(2c + d + 6f) = 0
(12c + 36d + 48f) + 2(2c + d + 6f) = 0
12c + 36d + 48f + (2c * 2 + d * 2 + 6f * 2) = 0
12c + 36d + 48f + (4c + 2d + 12f) = 0

Reorder the terms:
12c + 4c + 36d + 2d + 48f + 12f = 0

Combine like terms: 12c + 4c = 16c
16c + 36d + 2d + 48f + 12f = 0

Combine like terms: 36d + 2d = 38d
16c + 38d + 48f + 12f = 0

Combine like terms: 48f + 12f = 60f
16c + 38d + 60f = 0

Solving
16c + 38d + 60f = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-38d' to each side of the equation.
16c + 38d + -38d + 60f = 0 + -38d

Combine like terms: 38d + -38d = 0
16c + 0 + 60f = 0 + -38d
16c + 60f = 0 + -38d
Remove the zero:
16c + 60f = -38d

Add '-60f' to each side of the equation.
16c + 60f + -60f = -38d + -60f

Combine like terms: 60f + -60f = 0
16c + 0 = -38d + -60f
16c = -38d + -60f

Divide each side by '16'.
c = -2.375d + -3.75f

Simplifying
c = -2.375d + -3.75f

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