12(9-7/12y)=3(3y+4)

Solution for 12(9-7/12y)=3(3y+4) equation:

12(9-7/12y)=3(3y+4)

We move all terms to the left:

12(9-7/12y)-(3(3y+4))=0


Domain of the equation: 12y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

12(-7/12y+9)-(3(3y+4))=0

We multiply parentheses

-84y-(3(3y+4))+108=0


We calculate terms in parentheses: -(3(3y+4)), so:

3(3y+4)

We multiply parentheses

9y+12

Back to the equation:

-(9y+12)


We get rid of parentheses

-84y-9y-12+108=0

We add all the numbers together, and all the variables

-93y+96=0

We move all terms containing y to the left, all other terms to the right

-93y=-96

y=-96/-93

y=1+1/31