12(8-n)=4(n-5)

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Solution for 12(8-n)=4(n-5) equation: 



12(8-n)=4(n-5)

We move all terms to the left:

12(8-n)-(4(n-5))=0

We add all the numbers together, and all the variables

12(-1n+8)-(4(n-5))=0

We multiply parentheses

-12n-(4(n-5))+96=0



We calculate terms in parentheses: -(4(n-5)), so:

4(n-5)

We multiply parentheses

4n-20

Back to the equation:

-(4n-20)



We get rid of parentheses

-12n-4n+20+96=0

We add all the numbers together, and all the variables

-16n+116=0

We move all terms containing n to the left, all other terms to the right

-16n=-116

n=-116/-16

n=7+1/4

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