12(6-2d)+4d=48

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Solution for 12(6-2d)+4d=48 equation: 



12(6-2d)+4d=48

We move all terms to the left:

12(6-2d)+4d-(48)=0

We add all the numbers together, and all the variables

12(-2d+6)+4d-48=0

We add all the numbers together, and all the variables

4d+12(-2d+6)-48=0

We multiply parentheses

4d-24d+72-48=0

We add all the numbers together, and all the variables

-20d+24=0

We move all terms containing d to the left, all other terms to the right

-20d=-24

d=-24/-20

d=1+1/5

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