12(5+2y)=4y-(5-4y)

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Solution for 12(5+2y)=4y-(5-4y) equation: 



12(5+2y)=4y-(5-4y)

We move all terms to the left:

12(5+2y)-(4y-(5-4y))=0

We add all the numbers together, and all the variables

12(2y+5)-(4y-(-4y+5))=0

We multiply parentheses

24y-(4y-(-4y+5))+60=0



We calculate terms in parentheses: -(4y-(-4y+5)), so:

4y-(-4y+5)

We get rid of parentheses

4y+4y-5

We add all the numbers together, and all the variables

8y-5

Back to the equation:

-(8y-5)



We get rid of parentheses

24y-8y+5+60=0

We add all the numbers together, and all the variables

16y+65=0

We move all terms containing y to the left, all other terms to the right

16y=-65

y=-65/16

y=-4+1/16

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