12(4r-5/6r)+20=19r-5+45/2r

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Solution for 12(4r-5/6r)+20=19r-5+45/2r equation:



12(4r-5/6r)+20=19r-5+45/2r
We move all terms to the left:
12(4r-5/6r)+20-(19r-5+45/2r)=0
Domain of the equation: 6r)!=0
r!=0/1
r!=0
r∈R
Domain of the equation: 2r)!=0
r!=0/1
r!=0
r∈R
We add all the numbers together, and all the variables
12(+4r-5/6r)-(19r+45/2r-5)+20=0
We multiply parentheses
48r-60r-(19r+45/2r-5)+20=0
We get rid of parentheses
48r-60r-19r-45/2r+5+20=0
We multiply all the terms by the denominator
48r*2r-60r*2r-19r*2r+5*2r+20*2r-45=0
Wy multiply elements
96r^2-120r^2-38r^2+10r+40r-45=0
We add all the numbers together, and all the variables
-62r^2+50r-45=0
a = -62; b = 50; c = -45;
Δ = b2-4ac
Δ = 502-4·(-62)·(-45)
Δ = -8660
Delta is less than zero, so there is no solution for the equation

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