12(3x-1)=10(3x+1)+20

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Solution for 12(3x-1)=10(3x+1)+20 equation: 



12(3x-1)=10(3x+1)+20

We move all terms to the left:

12(3x-1)-(10(3x+1)+20)=0

We multiply parentheses

36x-(10(3x+1)+20)-12=0



We calculate terms in parentheses: -(10(3x+1)+20), so:

10(3x+1)+20

We multiply parentheses

30x+10+20

We add all the numbers together, and all the variables

30x+30

Back to the equation:

-(30x+30)



We get rid of parentheses

36x-30x-30-12=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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