12(3d+4)=6(7d+2)

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Solution for 12(3d+4)=6(7d+2) equation: 



12(3d+4)=6(7d+2)

We move all terms to the left:

12(3d+4)-(6(7d+2))=0

We multiply parentheses

36d-(6(7d+2))+48=0



We calculate terms in parentheses: -(6(7d+2)), so:

6(7d+2)

We multiply parentheses

42d+12

Back to the equation:

-(42d+12)



We get rid of parentheses

36d-42d-12+48=0

We add all the numbers together, and all the variables

-6d+36=0

We move all terms containing d to the left, all other terms to the right

-6d=-36

d=-36/-6

d=+6

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