12(3b-b/4a)=36

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Solution for 12(3b-b/4a)=36 equation: 


x in (-oo:+oo)

12*(3*b-(a*(b/4))) = 36 // - 36

12*(3*b-(a*(b/4)))-36 = 0

12*(3*b-1/4*a*b)-36 = 0

12*(3*b-1/4*a*b)-36 = 0

36*b-3*a*b-36 = 0

36*b-3*a*b-36 = 0

x belongs to the empty set

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