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12(3+y)=5(2y-8)
We move all terms to the left:
12(3+y)-(5(2y-8))=0
We add all the numbers together, and all the variables
12(y+3)-(5(2y-8))=0
We multiply parentheses
12y-(5(2y-8))+36=0
We calculate terms in parentheses: -(5(2y-8)), so:We get rid of parentheses
5(2y-8)
We multiply parentheses
10y-40
Back to the equation:
-(10y-40)
12y-10y+40+36=0
We add all the numbers together, and all the variables
2y+76=0
We move all terms containing y to the left, all other terms to the right
2y=-76
y=-76/2
y=-38
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