12(3+y)=5(-2y+5)

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Solution for 12(3+y)=5(-2y+5) equation: 



12(3+y)=5(-2y+5)

We move all terms to the left:

12(3+y)-(5(-2y+5))=0

We add all the numbers together, and all the variables

12(y+3)-(5(-2y+5))=0

We multiply parentheses

12y-(5(-2y+5))+36=0



We calculate terms in parentheses: -(5(-2y+5)), so:

5(-2y+5)

We multiply parentheses

-10y+25

Back to the equation:

-(-10y+25)



We get rid of parentheses

12y+10y-25+36=0

We add all the numbers together, and all the variables

22y+11=0

We move all terms containing y to the left, all other terms to the right

22y=-11

y=-11/22

y=-1/2

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