12(2x-4)-8(3x+1)=10x

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Solution for 12(2x-4)-8(3x+1)=10x equation: 



12(2x-4)-8(3x+1)=10x

We move all terms to the left:

12(2x-4)-8(3x+1)-(10x)=0

We add all the numbers together, and all the variables

-10x+12(2x-4)-8(3x+1)=0

We multiply parentheses

-10x+24x-24x-48-8=0

We add all the numbers together, and all the variables

-10x-56=0

We move all terms containing x to the left, all other terms to the right

-10x=56

x=56/-10

x=-5+3/5

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