12(2x-3)-14(2x-3)=10(3x+5)+12

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Solution for 12(2x-3)-14(2x-3)=10(3x+5)+12 equation: 



12(2x-3)-14(2x-3)=10(3x+5)+12

We move all terms to the left:

12(2x-3)-14(2x-3)-(10(3x+5)+12)=0

We multiply parentheses

24x-28x-(10(3x+5)+12)-36+42=0



We calculate terms in parentheses: -(10(3x+5)+12), so:

10(3x+5)+12

We multiply parentheses

30x+50+12

We add all the numbers together, and all the variables

30x+62

Back to the equation:

-(30x+62)



We add all the numbers together, and all the variables

-4x-(30x+62)+6=0

We get rid of parentheses

-4x-30x-62+6=0

We add all the numbers together, and all the variables

-34x-56=0

We move all terms containing x to the left, all other terms to the right

-34x=56

x=56/-34

x=-1+11/17

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