12(2x-1)=8(2x+1)+28

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Solution for 12(2x-1)=8(2x+1)+28 equation: 



12(2x-1)=8(2x+1)+28

We move all terms to the left:

12(2x-1)-(8(2x+1)+28)=0

We multiply parentheses

24x-(8(2x+1)+28)-12=0



We calculate terms in parentheses: -(8(2x+1)+28), so:

8(2x+1)+28

We multiply parentheses

16x+8+28

We add all the numbers together, and all the variables

16x+36

Back to the equation:

-(16x+36)



We get rid of parentheses

24x-16x-36-12=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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