12(2x+9)=6(2x+28)

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Solution for 12(2x+9)=6(2x+28) equation: 



12(2x+9)=6(2x+28)

We move all terms to the left:

12(2x+9)-(6(2x+28))=0

We multiply parentheses

24x-(6(2x+28))+108=0



We calculate terms in parentheses: -(6(2x+28)), so:

6(2x+28)

We multiply parentheses

12x+168

Back to the equation:

-(12x+168)



We get rid of parentheses

24x-12x-168+108=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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