12(2k+12)=24(3k-2)

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Solution for 12(2k+12)=24(3k-2) equation: 



12(2k+12)=24(3k-2)

We move all terms to the left:

12(2k+12)-(24(3k-2))=0

We multiply parentheses

24k-(24(3k-2))+144=0



We calculate terms in parentheses: -(24(3k-2)), so:

24(3k-2)

We multiply parentheses

72k-48

Back to the equation:

-(72k-48)



We get rid of parentheses

24k-72k+48+144=0

We add all the numbers together, and all the variables

-48k+192=0

We move all terms containing k to the left, all other terms to the right

-48k=-192

k=-192/-48

k=+4

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