12(27)=(x+8)(x+8)

Solution for 12(27)=(x+8)(x+8) equation:

12(27)=(x+8)(x+8)

We move all terms to the left:

12(27)-((x+8)(x+8))=0

We multiply parentheses ..

-((+x^2+8x+8x+64))+1227=0


We calculate terms in parentheses: -((+x^2+8x+8x+64)), so:

(+x^2+8x+8x+64)

We get rid of parentheses

x^2+8x+8x+64

We add all the numbers together, and all the variables

x^2+16x+64

Back to the equation:

-(x^2+16x+64)


We get rid of parentheses

-x^2-16x-64+1227=0

We add all the numbers together, and all the variables

-1x^2-16x+1163=0

a = -1; b = -16; c = +1163;
Δ = b2-4ac
Δ = -162-4·(-1)·1163
Δ = 4908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4908}=\sqrt{4*1227}=\sqrt{4}*\sqrt{1227}=2\sqrt{1227}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{1227}}{2*-1}=\frac{16-2\sqrt{1227}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{1227}}{2*-1}=\frac{16+2\sqrt{1227}}{-2}
$