12(1+8n)=-n-4(-3+4n)

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Solution for 12(1+8n)=-n-4(-3+4n) equation: 



12(1+8n)=-n-4(-3+4n)

We move all terms to the left:

12(1+8n)-(-n-4(-3+4n))=0

We add all the numbers together, and all the variables

12(8n+1)-(-n-4(4n-3))=0

We multiply parentheses

96n-(-n-4(4n-3))+12=0



We calculate terms in parentheses: -(-n-4(4n-3)), so:

-n-4(4n-3)

We add all the numbers together, and all the variables

-1n-4(4n-3)

We multiply parentheses

-1n-16n+12

We add all the numbers together, and all the variables

-17n+12

Back to the equation:

-(-17n+12)



We get rid of parentheses

96n+17n-12+12=0

We add all the numbers together, and all the variables

113n=0

n=0/113

n=0

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