12(1+6b)=6b-6(b+10)

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Solution for 12(1+6b)=6b-6(b+10) equation: 



12(1+6b)=6b-6(b+10)

We move all terms to the left:

12(1+6b)-(6b-6(b+10))=0

We add all the numbers together, and all the variables

12(6b+1)-(6b-6(b+10))=0

We multiply parentheses

72b-(6b-6(b+10))+12=0



We calculate terms in parentheses: -(6b-6(b+10)), so:

6b-6(b+10)

We multiply parentheses

6b-6b-60

We add all the numbers together, and all the variables

-60

Back to the equation:

-(-60)



We add all the numbers together, and all the variables

72b+72=0

We move all terms containing b to the left, all other terms to the right

72b=-72

b=-72/72

b=-1

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